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Any mathematicians?


Peter Bell

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OK, apologies if this is very nerdy... 🙂

 

For any equation:

y=ax + b

the line crosses the y axis at b with a gradient of a. 

So, for y=x-1, the line crosses the y axis at -1 with a gradient of 1 (as it is a positive gradient, the line goes up from left to right (uphill)). 

To solve simultaneous equations, rearrange one of the equations to be 'x=' and then substitute it into the other equation, so:

Rearrange y=x-1 into:

x=y+1

Substitute back into y=7-x to give:

y=7-(y+1)

y=7-y-1

2y=6

y=3

Then put y back into the first equation, y=7-x to give:

3=7-x

x=7-3

x=4

Dull, huh? 

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3 hours ago, richyb66 said:

I have maths skills that I've never needed to use in the last 40 years.

How very true --- was using Calculus in 5th form --- could never understand the principle of there being two possible answers --- never needed to remember/use since.

And there is always an electric calculator somewhere --- if you know which buttons to press.

All present retirement calcs just need me to know the trig laws. 

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3 hours ago, richyb66 said:

I have maths skills that I've never needed to use in the last 40 years.

I do a weekly quiz with some old colleagues - one of the questions is a long, wordy thing that almost always requires the use of simultaneous equations to solve, so I get regular practice 🙂 .

Also a son who did his GCSEs last year and a daughter coming up to doing them now...further practice.

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